Problem Description –
Write an SQL query to find for each month and country, the number of transactions and their total amount, the number of approved transactions and their total amount.
Return the result table in any order.
The query result format is in the following example.
Difficulty Level – Medium
Problem Link – Monthly Transactions
SELECT DATE_FORMAT(trans_date, '%Y-%m') as month, country, COUNT(*) as trans_count, SUM(CASE WHEN state ='approved' THEN 1 ELSE 0 END) as approved_count, SUM(amount) as trans_total_amount, SUM(CASE WHEN state='approved' THEN amount ELSE 0 END) as approved_total_amount FROM Transactions GROUP BY 1, 2